What will be the voltage drop across a 10-ohm resistor in a series circuit if a 5 amp fuse blows?

In a series circuit, the current through all components is the same and is equal to the current flowing from the power source. The voltage drop across a resistor can be determined using Ohm's Law, which states that the voltage (V) is equal to the current (I) multiplied by the resistance (R), or V = I × R.

In this scenario, if a 5 amp fuse blows, it indicates there is an overcurrent condition in the circuit. This typically means that the circuit is open, and no current is flowing through it anymore. Therefore, despite the presence of the 10-ohm resistor, since the circuit is open and there is no current, the voltage drop across the resistor would be zero volts.

So, the correct answer reflects the fact that with no current flowing due to the blown fuse, there cannot be any voltage drop across the resistor. This understanding of how series circuits function and the implications of a fuse blowing are key concepts in electrical work.