If the peak value of voltage is 340 volts, what is the effective value of voltage?

Study for the 2nd Year Lineman Apprentice Exam. Utilize flashcards and multiple-choice questions with explanations and hints. Prepare effectively for your exam!

To find the effective value (also known as the root mean square or RMS value) of an AC voltage, you typically use the relationship between the peak voltage and the effective voltage. The effective voltage is calculated by taking the peak voltage and dividing it by the square root of 2.

The formula is as follows:

[ \text{Effective Voltage} = \frac{\text{Peak Voltage}}{\sqrt{2}} ]

In this case, the peak voltage is given as 340 volts. Therefore, you would calculate it as:

[ \text{Effective Voltage} = \frac{340 \text{ volts}}{\sqrt{2}} \approx 240 \text{ volts} ]

This calculation shows that the effective voltage for an AC signal with a peak voltage of 340 volts is approximately 240 volts, which matches the provided choice. Knowing this relationship is important for understanding how voltage levels are measured and utilized in electrical systems, as the RMS value is essential for calculating power in AC circuits.

The other choices do not conform to the established relationship between peak and effective voltage for standard AC applications.

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy