How much power is lost if a load current of 25 amps is drawn through a line resistance of 6.4 ohms?

Study for the 2nd Year Lineman Apprentice Exam. Utilize flashcards and multiple-choice questions with explanations and hints. Prepare effectively for your exam!

To determine the power loss due to resistance in a conductor, the power loss can be calculated using the formula:

Power Loss (P) = I²R

where I is the current in amperes and R is the resistance in ohms.

In this scenario, the load current is 25 amps and the line resistance is 6.4 ohms. Plugging these values into the formula:

P = (25 amps)² * (6.4 ohms)

P = 625 * 6.4

P = 4000 watts

Thus, the power lost in the line due to the resistance is 4000 watts. This relationship between current, resistance, and power is critical in understanding how energy is dissipated in electrical systems. Higher current or resistance will result in greater power loss, which underscores the importance of using adequately sized conductors to minimize such losses in a real-world electrical system.

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